10y^2-8y+3=0

Solution for 10y^2-8y+3=0 equation:

Simplifying
10y2 + -8y + 3 = 0

Reorder the terms:
3 + -8y + 10y2 = 0

Solving
3 + -8y + 10y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
10 the coefficient of the squared term: 

Divide each side by '10'.
0.3 + -0.8y + y2 = 0

Move the constant term to the right:

Add '-0.3' to each side of the equation.
0.3 + -0.8y + -0.3 + y2 = 0 + -0.3

Reorder the terms:
0.3 + -0.3 + -0.8y + y2 = 0 + -0.3

Combine like terms: 0.3 + -0.3 = 0.0
0.0 + -0.8y + y2 = 0 + -0.3
-0.8y + y2 = 0 + -0.3

Combine like terms: 0 + -0.3 = -0.3
-0.8y + y2 = -0.3

The y term is -0.8y.  Take half its coefficient (-0.4).
Square it (0.16) and add it to both sides.

Add '0.16' to each side of the equation.
-0.8y + 0.16 + y2 = -0.3 + 0.16

Reorder the terms:
0.16 + -0.8y + y2 = -0.3 + 0.16

Combine like terms: -0.3 + 0.16 = -0.14
0.16 + -0.8y + y2 = -0.14

Factor a perfect square on the left side:
(y + -0.4)(y + -0.4) = -0.14

Can't calculate square root of the right side.

The solution to this equation could not be determined.